(5x-4+2x^2)(3+4x)=

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Solution for (5x-4+2x^2)(3+4x)= equation: 


Simplifying
(5x + -4 + 2x2)(3 + 4x) = 0

Reorder the terms:
(-4 + 5x + 2x2)(3 + 4x) = 0

Multiply (-4 + 5x + 2x2) * (3 + 4x)
(-4(3 + 4x) + 5x * (3 + 4x) + 2x2 * (3 + 4x)) = 0
((3 * -4 + 4x * -4) + 5x * (3 + 4x) + 2x2 * (3 + 4x)) = 0
((-12 + -16x) + 5x * (3 + 4x) + 2x2 * (3 + 4x)) = 0
(-12 + -16x + (3 * 5x + 4x * 5x) + 2x2 * (3 + 4x)) = 0
(-12 + -16x + (15x + 20x2) + 2x2 * (3 + 4x)) = 0
(-12 + -16x + 15x + 20x2 + (3 * 2x2 + 4x * 2x2)) = 0
(-12 + -16x + 15x + 20x2 + (6x2 + 8x3)) = 0

Combine like terms: -16x + 15x = -1x
(-12 + -1x + 20x2 + 6x2 + 8x3) = 0

Combine like terms: 20x2 + 6x2 = 26x2
(-12 + -1x + 26x2 + 8x3) = 0

Solving
-12 + -1x + 26x2 + 8x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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